INTA-110
# interview assessment questions
# Spiral Matrix
// Print matrix in spiral form
#include <bits/stdc++.h>
using namespace std;
#define R 3
#define C 6
void spiralPrint(int m, int n, int a[R][C])
{
int i, k = 0, l = 0;
/* k - starting row index
m - ending row index
l - starting column index
n - ending column index
i - iterator
*/
while (k < m && l < n) {
/* Print the first row from
the remaining rows */
for (i = l; i < n; ++i) {
cout << a[k][i] << " ";
}
k++;
/* Print the last column
from the remaining columns */
for (i = k; i < m; ++i) {
cout << a[i][n - 1] << " ";
}
n--;
/* Print the last row from
the remaining rows */
if (k < m) {
for (i = n - 1; i >= l; --i) {
cout << a[m - 1][i] << " ";
}
m--;
}
/* Print the first column from
the remaining columns */
if (l < n) {
for (i = m - 1; i >= k; --i) {
cout << a[i][l] << " ";
}
l++;
}
}
}
/* Driver program to test above functions */
int main()
{
int a[R][C] = { { 1, 2, 3, 4, 5, 6 },
{ 7, 8, 9, 10, 11, 12 },
{ 13, 14, 15, 16, 17, 18 } };
spiralPrint(R, C, a);
return 0;
}
